Thursday, June 20, 2019

Maybe there is no "best"

As a cleaner example of what I was trying to get at in my blog of 13 June consider agents that can have 3 different means of attack: V1, V2, and V3 along with 3 means of countering these same  attacks: -V1,-V2, and -V3. Each agent is then described by a vector (V1, V2, V3, -V1, -V2, -V3). If agent A=(1,0,0,0,1,0), agent B=(0,1,0,0,0,1) and agent C=(0,0,1,1,0,0), then agent A will always beat agent B*, agent B will always beat agent C, and agent C will always beat agent A. There will be no "best", no "fittest."

* i.e., A can attack B using V1, which B can not defend against, while countering B's V2 attacks using its -V2 defense.

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